A simple procedure for writing electron Lewis dot structures was given in a previous post entitled “Lewis Structures and the Octet Rule”.
Several worked examples relevant to this procedure were given in previous posts please see the Sitemap - Table of Contents (Lewis Electron Dot Structures).
Let us examine the case of chlorosulphonic acid HSO3Cl . How can we construct the chlorosulphonic acid Lewis dot structure?
Step 1: Connect the atoms with single bonds.
Step 2: Calculate the # of electrons in π bonds (multiple bonds) using formula (1):
Fig. 1 : Connect the atoms of chlorosulphonic acid with single bonds. |
Step 2: Calculate the # of electrons in π bonds (multiple bonds) using formula (1):
Where n in this case is 5 since HSO3Cl consists of six atoms but one of them is a H atom.
Where V = (1 + 6 + 6 * 3 + 7) = 26
Therefore, P = 6n + 2 – V = 6 * 5 + 2 – 32 = 0 So there are no π electrons in HSO3Cl
Step 3 & 4: The Lewis structures of HSO3Cl are derived below:
Fig. 2 : Plausible Lewis structure of the chlorosulphonic acid. |
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