How do I draw the Lewis electron dot structure of cyanamide CN2H2?
A simple and general procedure for writing Lewis structures is given in a previous article entitled “Lewis Structures and the Octet Rule”. Relevant worked examples were given in the following articles: Examples #1, #2, #3 , #4, #5, #6, #7, #8, #9, #10, #11, #12, #13, #14, #15, #16, #17, #18, #19, #20, #21, #22, #23, #24, #25, #26, #27, #28, #29, #30, #31, #32, #33 and #34.
Let us consider the case of cyanamide CN2H2.
Step 1: Connect the atoms with single bonds.
Fig. 1: Connect the atoms of the CN2H2 molecule with single bonds. |
Step 2: Calculate the # of electrons in π bonds (multiple bonds) using formula (1):
Where n in this case is 3 since CN2H2 has 3 non-hydrogen atoms.
Where V = 5*2 + 4 + 1*2 = 16
Therefore, P = 6n + 2 – V = 6 *3 + 2 – 16 = 4 So there are either 2 double bonds or 1 triple bond.
Step 3 & 4: The Lewis dot structures of CN2H2 areas follows:
Fig. 2: Lewis electron dot structures of the cyanamide CN2H2. |
Lewis electron dot Structure #1 is the major contributor to the hybrid because it is more stable than #2 (octet of electrons around each atom and no charge sepatation).
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