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Senin, 01 Februari 2010

Chemistry Topics Tested in IIT JEE 2009 Question Paper I

1. Van Der Waal's Equation for Real Gases

2. Writing compound name of 2-Bromo-5-hydroxybenzonitrile given the pictorial view of the molecule.
(Cyanide group has higher priority than phenol. Hence correct IUPAC name is
2-Bromo-5-hydroxybenzonitrile)

3. Atomic mass of an element having isotopes

Given that the abundances of isotopes 54Fe, 56Fe and 57Fe are 5%, 90% and 5 %, respectively, the atomic mass of Fe is -
(A) 55.85 (B) 55.95
(C) 55.75 (D) 56.05
[Ans. B]

4. Polymers

Among cellulose, poly(vinyl chloride), nylon and natural rubber, the polymer in which the intermolecular
force of attraction is weakest is -
(A) Nylon (B) Poly(vinyl chloride)
(C) Cellulose (D) Natural Rubber
[Ans. D]
Sol. Natural rubber is an example of elastomers, which has weakest intermolecular forces (dispersion forces).

5. Henry's Law

The solubility of a gas is related to its pressure by Henry's law.

The mass of a gas dissolved per unit volume of the solvent at a given temperature is proportional to the pressure of the gas in equilibrium with the solution.

m = Kp

m = mass of the gas dissolved in a unit volume of the solvent.
p = is the pressure of the gas in equilibrium with the solution
K = proportionality constant

Alternative statement

The pressure of a gas over a solution in which the gas is dissolved is proportional to the mole fraction of the gas dissolved in the solution.

p = Kx

p = partial vapour pressure
x = mole fraction of the gas in the solvent
K = Henry's law constant

Problem
The Henry's law constant for the solubility of N2 gas in water at 298 K is 1.0 × 105

atm. The mole fraction of N2 in air is 0.8. The number of moles of N2 from air dissolved in 10 moles of water at 298 K and 5 atm
pressure is -

Answer: 4.0 × 10-4

6. Acidity order of aromatic carboxylic acids and phenol

Benzoic acid (–COOH) is more acidic than phenol. Electron withdrawing group increase acidic nature &
electron donating group decrease acidity.

7. Among the electrolytes Na2SO4, CaCl2, Al2(SO4)3 and NH4Cl, the most effective coagulating agent for
Sb2S3 sol is -

Sb2S3 is negatively charged sols. Because of the formation higher positive charge ions coagulating power
of Al2(SO4)3 is the highest

8. Reactions of Phosphorous

The reaction of P4 with X leads selectively to P4O6. The X is -

(A) Dry O2 (B) A mixture of O2 and N2
(C) Moist O2 (D) O2 in the presence of aqueous NaOH

Answer B
P4 is converted to P4O6 in the presence of limited supply of oxygen.

9. Reactions of Sodium

The compound(s) formed upon combustion of sodium metal in excess air is(are) -

10. Defects of Solids

The correct statement(s) regarding defects in solids is(are) -

(A) Frenkel defect is usually favoured by a very small difference in the size of cation and anion
(B) Frenkel defect is a dislocation defect
(C) Trapping of an electron in the lattice leads to the formation of F-center
(D) Schottky defects have no effect on the physical properties of solids

Answers: B,C

11. Geometrical isomerism of organometallic compounds

12. Stereoisomers

The correct statement(s) about the compound H3C(HO)HC–CH=CH–CH(OH)CH3 (X) is (are)
(A) The total number of stereoisomers possible for X is 6
(B) The total number of diastereomers possible for X is 3
(C) If the stereochemistry about the double bond in X is trans, the number of enantiomers possible for X is 4
(D) If the stereochemistry about the double bond in X is cis, the number of enantiomers possible for X is 2

Answer: A,D

13. Anilines

p-Amino-N, N-dimethylaniline is added to a strongly acidic solution of X. The resulting solution is treated
with a few drops of aqueous solution of Y to yield blue coloration due to the formation of methylene blue.
Treatment of the aqueous solution of Y with the reagent potassium hexacyanoferrate (II) leads to the
formation of an intense blue precipitate. The precipitate dissolves on excess addition of the reagent.
Similarly, treatment of the solution of Y with the solution of potassium hexacyanoferrate (III) leads to a
brown coloration due to the formation of Z.

Questions: Find compound X,Y and Z

14. Carbonyl Compounds

A carbonyl compound P, which gives positive iodoform test, undergoes reaction with MeMgBr followed
by dehydration to give an olefin Q. Ozonolysis fo Q leads to a dicarbonyl compound R, Which undergoes
intramolecular aldol reaction to give predominantly S.


Questions asked on Structure of P,Q,R and S

15. Attaching these properties to elements in matching
(p) Paramagnetic
(q) Undergoes oxidation
(r) Undergoes reduction
(s) Bond order ≥ 2
(t) Mixing of 's' and 'p' orbitals

16. Matching of characteristic reactions with compounds


(p) Reduction with H2/Pd-C
(q) Reduction with SnCl2/HCl
(r) Development of foul smell on treatment with chloroform and
alcoholic KOH
(s) Reduction with disobutylaluminium hydride (DIBAL-H)
(t) Alkaline hydrolysis

Compounds

(A) CH3CH2CH2CN, (B) CH3CH2OCOCH3, (C) CH3 – CH = CH – CH2OH, (D) CH3CH2CH2CH2NH2

For question paper

Rabu, 23 Januari 2008

IIT JEE Revision Ch. 31 Carbohydrates - Core Points

JEE Syllabus

Carbohydrates:
Classification;
mono and di-saccharides (glucose and sucrose);
Oxidation, reduction,
glycoside formation and hydrolysis of sucrose.
----------

1. Carbohydrates means "hydrates of carbon".
These are poly-hydroxylated-aldehydes or poly-hydroxylated-ketones. The general formula is C-x(H-2O)-y

2. Carbohydrates are classified as:
Monosaccharides, Oligosaccharides, Polysaccharides

3. Glucose is a monosaccharide and it forms a six membered ring of five carbon atoms and one oxygen atom.

4. When acqueous solution of glucose is treated with sodium amalgam or sodium borohydride, it is reduced to sorbitol (or glucito) a hexahydric alcohol.

5. Mild oxidizing agents such as bromine water, silver oxide, sodium hypobromite etc. oxidize glucose ot gluconic acid converting -CHO group to -COOH group.


6. The important members belonging to disaccharides are sucrose, maltose and lactose.

7. On hydrolysis these give two molecules of monosaccharides.

8. Sucrose in comination with water (hydrolysis) gives glucose and fructose.

9. Sucrose is composed of alpha-D-glucose and beta-D-fructose. These units are held together by alpha, beta-glycosidic linkage between C1 (carbon 1) of the glucose unit (pyranose ring) and C2 of the fructose unit (furanose ring).


10. Reducing sugars are easily oxidized to give carboxylic acid.

Detailed review points for each topic in the syllabus follow this post. Click Older Post

IIT JEE Revision Ch. 32 Amino Acids and Peptides Core Point

Amino acids and peptides:
General structure (only primary structure for peptides) and
physical properties.
------------

Chapter Core Points

amino acids are organic compounds containing both an amino group (NH2) and carboxylic group (COOH). They are represented by the general formula:
R
|
C-COOH
|
NH2

amino acids contain an amino group attached to alpha carbon of a carboxylic acid.

Amino acids are the basic units of proteins.

There are twenty amino acids commonly found in proteins.



Except Glycine all other amino acids contain asymmetric carbon atom next to the carboxylic acid.

Peptide linkage: The condensation of two amino acids with the eliminatin of H2O (H from NH2 and OH from the acid side produces CO-NH linkage, which in protein chemistry is known as peptide linkage.

IIT JEE Revision - Ch.33 Polymers - Core Points

JEE syllabus

Properties and uses of some important polymers:
Natural rubber,
cellulose,
nylon,
teflon and
PVC.
------------

Objective 10 points

A polymer is a large molecule built by repetitive binding together of many small units called monomers.

Homopolymer: A polymer derived from a single repeating monomer. Only one type of monomer will have repetitive binding and a large molecule appears.

Copolymer: When two or more monomer bind together in a repetitive manner and give rise to a large polymer, it is called copolymer.

Chain growth polymers: Also called addition polymers.

Step Growth polymerss: Also called as condensation polymers

Classification based on physical properties: Elastomers, Fibre, Thermoplastics and
Thermosetting plastics


Rubber is a naturally occuring polymer of isoprene (2-methyl buta-1,3-diene)

Natural rubber is a thermoplastic and becomes soft and sticky when heated.The properties can be modified and improved by the process of vulcanization.

cellulose: It is a polymer of glucose. It is a chief structural material of the plants.

Nylon: The monomer of nylon 6 is caprolactum and for nylon 66, the monomers are hexamethylenediamine and adipic acid.


Teflon: It is an addition polymer of tetrafluoroethylene (nF2C=CF2).Under heat and pressure the double bond breaks and gets ready for bonding with a carbon on either side and the polymerisation takes place. (-F2C-CF2-)n


PVC: PVC is polyvinyl chloride and its monomer is vinyl chloride. CH2=CHCl

Detailed revision points of this chapter follow this blog. Click on older post